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Year 10 - Science

Calculating from displacement-time graphs (v = s ÷ t)

Measuring and calculating motion

Unit Summary

This unit covers vector-scalar distinctions in displacement, distance, velocity, and speed. It explores speeds, acceleration, motion graphs, and formulas for uniform and non-uniform motion. It also includes understanding circular motion and conducting accurate measurements, and calculations.

Lesson Summary

You will learn to take readings from displacement-time graphs to find distance, displacement, speed and velocity.

Key Notes

  • The velocity of an object is equal to the gradient of a displacement-time graph.
  • A direction in which velocity and displacement are measured needs to be chosen.
  • A negative gradient on a displacement-time graph (sloping downwards) represents velocity in the opposite direction.
  • A negative value for displacement represents a position 'behind' the starting position.

Vocabulary To Learn

  • displacement-time graph: A displacement-time graph shows the change in displacement over a time period. The displacement along a straight line can be positive or negative.
  • gradient: The gradient on a displacement-time graph gives the instantaneous velocity.
  • instantaneous velocity: The instantaneous velocity is the velocity of an object at a particular moment in time.

Common Mistakes To Avoid

  • A pair of coordinates on a s-t graph can be used to calculate the instantaneous speed or velocity at that point, but that only works for a straight line graph through the origin.

3 Quick Questions (With Answers)

1. Explain the scientific idea in this lesson using two key points.

The velocity of an object is equal to the gradient of a displacement-time graph. A direction in which velocity and displacement are measured needs to be chosen.

2. Define this scientific word and use it in context. 'displacement-time graph'

A displacement-time graph shows the change in displacement over a time period. The displacement along a straight line can be positive or negative. Include the word in a full scientific explanation, not as a single label.

3. Correct this common scientific misunderstanding.

Mistake: A pair of coordinates on a s-t graph can be used to calculate the instantaneous speed or velocity at that point, but that only works for a straight line graph through the origin. Correction: Ask pupils to calculate the velocity of a graph that represents a steady velocity on a line that does not go through the origin, and to check to see if dividing the values at any point on the line gives the right value for velocity.

More Lessons In This Unit

Browse all guides in the Year 10 Science guide library.