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Year 11 - Maths

Advanced problem solving with further surface area and volume

2D and 3D shape: surface area and volume (pyramids, spheres and cones)

Unit Summary

In this unit, pupils will further develop their understanding of shapes by considering the surface area and volume of pyramids, spheres and cones.

Lesson Summary

You will learn to use your enhanced knowledge of surface area and volume to solve problems.

Key Notes

  • The surface area of any solid can be calculated by a known method.
  • The volume of any solid can be calculated by a known method.
  • Writing an algebraic statement about surface area/volume can be done from a diagram.

Vocabulary To Learn

  • Volume: The volume is the amount of space occupied by a closed 3D shape.
  • Surface area: The surface area is the total area of all the surfaces of a closed 3D shape. The surfaces include all faces and any curved surfaces.
  • Compound shape: A compound shape is a shape created using two or more basic shapes. A composite shape is an alternative for compound shape.

Common Mistakes To Avoid

  • When questions are in context, the length may be described as the depth or height and this can cause some pupils to struggle if they have learned a formula with a particular word.

3 Quick Questions (With Answers)

1. Solve this in steps: explain the method from this lesson and why each step matters.

The surface area of any solid can be calculated by a known method. The volume of any solid can be calculated by a known method.

2. Use this key word in a maths sentence and explain it clearly. 'Volume'

The volume is the amount of space occupied by a closed 3D shape. Use this word when showing your method, then check your final answer is reasonable.

3. Spot and fix this common maths mistake.

Mistake: When questions are in context, the length may be described as the depth or height and this can cause some pupils to struggle if they have learned a formula with a particular word. Correction: Remind pupils that the volume of a 3D shape comes from the area of a cross section multiplied by the height or depth. They may need to evaluate a perpendicular length from other given information, using trigonometry or Pythagoras' theorem.

More Lessons In This Unit

Browse all guides in the Year 11 Maths guide library.